Question

1÷2(6+4x)-1÷4(8x-12=1÷2(2×-4)

Answer 1

I shall balance your parentheses and assume you meant

1÷2(6+4x)-1÷4(8x-12)=1÷2(2×-4)

That still looks odd, since you appear to have both "x" as a variable and "×" as a multiplication operator. I shall also assume that "×" means the variable "x", based on the overall syntax. That gives us the equation, using some extra spaces to aid in what I hope is clarity,

1÷2(6+4x) - 1÷4(8x-12) = 1÷2(2x-4)
or
1÷4(2x+3) - 1÷16(2x-3) = 1÷4(x-2)

Now, if we multiply through by the LCD to get rid of the fractions, we have

4(2x-3)(x-2) - (2x+3)(x-2) = 4(2x+3)(4x-3)
Now, expanding all that out and collecting terms, you end up with
6x^2-27x+30 = 32x^2+24x-36
26x^2+51x-66 = 0

Now just crank out the quadratic formula to get

x = (-51±√9465)/52

That seems unusually messy, so I may have made some incorrect assumptions. If so, then I'm sure you can fix things up.

Answer 2

I see a typo. Let's proceed from
4(2x-3)(x-2) - (2x+3)(x-2) = 4(2x+3)(2x-3)
6x^2-27x+30 = 16x^2-36
10x^2+27x-66 = 0

x = (-27±√3369)/20

Not much better.

Answer 3

1 + 2(6 + 4x) - 1 + 4(8x - 12) = 1 + 2(2x - 4).
Remove all parentheses by multiplying by the no. outside of it:
1 + 12 + 8x - 1 + 32x - 48 = 1 + 4x - 8,
Combine like-terms:
40x - 36 = 4x - 7,
36x = 29,
X = 29/36.