Asked by anonymous
A ball is shot straight up from the top of a 15-story building. The motion of the ball could be described by the function: h(t)= -16t^2 + 144t + 160 where t represents the time the ball is in the air in seconds and h(t) represents the height in feet .
What is the height of the ball after 4 seconds?
What is the maximum height of the ball?
At what time will the ball hit the ground?
What is the height of the ball after 4 seconds?
What is the maximum height of the ball?
At what time will the ball hit the ground?
Answers
Answered by
Steve
What is the height of the ball after 4 seconds?
Just plug in t=4
What is the maximum height of the ball?
recall that for ax^2+bx+c the vertex is at x = -b/2a
Also, less well known is that the y-coordinate of the vertex is (4ac-b^2)/4a
At what time will the ball hit the ground?
just solve for t when h=0
Just plug in t=4
What is the maximum height of the ball?
recall that for ax^2+bx+c the vertex is at x = -b/2a
Also, less well known is that the y-coordinate of the vertex is (4ac-b^2)/4a
At what time will the ball hit the ground?
just solve for t when h=0
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