Asked by juana
so I'm factoring quadratics and this is the problem; 2x^2-50
you would multiply a(c) which would just give me -100 but I don't know what to do after this.
you would multiply a(c) which would just give me -100 but I don't know what to do after this.
Answers
Answered by
jazmine
Since both terms are perfect squares, factor using the difference of squares formula, 2−b2=(a+b)(a−) where a=x and b=5 .
Remove unnecessary parentheses.2(x+5)(x−5)
2(x2−25)
Rewrite 25 as 5/2.
2(x2−5/2)
5/2= 5/2 as an exponent, the 2 is the exponent which should be floating over the five in the top right corner
Remove unnecessary parentheses.2(x+5)(x−5)
2(x2−25)
Rewrite 25 as 5/2.
2(x2−5/2)
5/2= 5/2 as an exponent, the 2 is the exponent which should be floating over the five in the top right corner
Answered by
Steve
Generally, we use ^ for exponents online
2x^2-50 = 2(x^2-25) = 2(x-5)(x+5)
2x^2-50 = 2(x^2-25) = 2(x-5)(x+5)
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