Asked by Babygirl

The “reaction time” of the average automobile driver is about 0.7 s. (The reaction time is the interval between the perception of a signal to stop and the application of the brakes.) If an automobile can slow down with an acceleration of 12 ft/s^2 compute the total distance(in feet) covered in coming to a stop after a signal is observed from an initial velocity of 55 mi/h. Let 1 mi/h= 1.466 ft/s.
271 ft
327 ft
113 ft
414 f

I have absolutely no idea. If you could please show me what to do and how to get the answer and check my answer. That would be amazing! Thanks!
Answered by bobpursley
distance before slowing: 55 *1.466ft/sec*.7sec=56.1ft check that.
distance while braking:
vf^2=vo^2+2ad
d= (55*1.466)^2/(2*12)=271ft

add the two distances
Answered by Babygirl
Thanks so much! You’re the GOAT!
Answered by Babygirl
Wait so is 271 the answer?
Answered by bobpursley
check it. Taking my answer is ridiculous. I am trying to show you how to work it.
Answered by bobpursley
and the answer is, no it is not the answer. Add the distances.
Answered by Babygirl
What distances? 12 and what else?
Answered by Babygirl
12 and 55?

If so, is the answer 338 which is not an answer choice.
Answered by bobpursley
56.1ft +271= ???
Answered by tommy
so whats the answer?
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