Asked by Banana
If ln a=2, ln b=3, and ln c=5, evaluate the following:
(a) ln(a^−2/b^4c^−3)=
-.9524
(b) ln(√b^−4*c^1*a^−1)=
-1.739
(c) ln(a^2b^4)/ln(bc)^−2=
42.39
(d) (ln(c^−1))*(ln(a/b^3))^−4=
-.03507
I am getting these answers but the problem gives me an error saying "at least ONE of my answers is incorrect"
I'm not sure how as I used the (ln) rules and broke it apart several times and even plugged it into my calculator and I am getting the same results.
can someone help me or point out what i am doing wrong.
rules:
log(ab)= log a +log b
log (a/b) = log a - log b
log a^b = b log a
(a) ln(a^−2/b^4c^−3)=
-.9524
(b) ln(√b^−4*c^1*a^−1)=
-1.739
(c) ln(a^2b^4)/ln(bc)^−2=
42.39
(d) (ln(c^−1))*(ln(a/b^3))^−4=
-.03507
I am getting these answers but the problem gives me an error saying "at least ONE of my answers is incorrect"
I'm not sure how as I used the (ln) rules and broke it apart several times and even plugged it into my calculator and I am getting the same results.
can someone help me or point out what i am doing wrong.
rules:
log(ab)= log a +log b
log (a/b) = log a - log b
log a^b = b log a
Answers
Answered by
scott
(a) ln[c^3 / (a^2 b^4)] = (5 * 3) - [(2 * 2) + (3 * 4)] = -1
(b) ln[c / (a b^2)] = 5 - [2 + (3 * 2)]
not sure how you are getting your results
... you shouldn't need a calculator
... just follow the rules carefully
(b) ln[c / (a b^2)] = 5 - [2 + (3 * 2)]
not sure how you are getting your results
... you shouldn't need a calculator
... just follow the rules carefully
Answered by
oghene-reumu
I think u are getting it wrong
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