Point Line
(−7, 6) x + y = 3
Write an equation of the line through the point parallel to the given line.
How do I start this
5 answers
see the question below (probably also posted by you). You have a point and a slope (that of the parallel line), so ...
what is the slope of x+y = 3 ?
y = -1 x + 3
slope = -1
so I need a line of form
y = -1 x + b that goes through (-7,6)
6 = 7 + b
b = -1
so
y = -1 x -1
or
x+y = -1
y = -1 x + 3
slope = -1
so I need a line of form
y = -1 x + b that goes through (-7,6)
6 = 7 + b
b = -1
so
y = -1 x -1
or
x+y = -1
y=-1x-1
and then y=1x+13
Those are my answers
and then y=1x+13
Those are my answers
y = 1 x + 13 has slope of +1
It is not parallel to x+y = 3 which has slope of -1
It is in fact perpendicular.
It is not parallel to x+y = 3 which has slope of -1
It is in fact perpendicular.
Sorry that is what I meant.
Y=-1x-1 is my parallel and the y=1x+13 is perpendicular
Y=-1x-1 is my parallel and the y=1x+13 is perpendicular
1 answer