Asked by Anonymous

You are given the dollar value of a product in 2012 and the rate at which the value of the product is expected to change during the next 5 years. Write a linear equation that gives the dollar value V of the product in terms of the year t. (Let t = 0 represent 2010.)

2012 value $950
Rate $350 increase per year

V(t)=??

Answers

Answered by Steve
you know that y=mt+b is the line which starts at b and grows by m for each successive value of t.

So, where does V start (when t=0), and how much does it grow when t increases by 1? That is, for each year?
Answered by Anonymous
V starts at 950?
Answered by Steve - update
Upon rereading the problem, I must revise my answer. You are given a point in 2012 (where t=2): (2,950)

and also the slope, or change each year. That is, m=350

So, using the point-slope form,

V(t) = 350(t-2)+950
Answered by Anonymous
So would that be my final answer or would I have to distribute?
Answered by Steve
depends how specific your teacher is.
To me, any correct form of the equation will do.
If you teacher specified the slope-intercept form, then yeah, expand it out.
But the point-slope form shows just how you got the equation, not just how well you can manipulate expressions.
Answered by Anonymous
Okay thank you. Here is another example with different numbers. Can you tell me if this is correct

You are given the dollar value of a product in 2012 and the rate at which the value of the product is expected to change during the next 5 years. Write a linear equation that gives the dollar value V of the product in terms of the year t. (Let t = 0 represent 2010.)

250t+500

Is this the point slope form as well
Answered by Anonymous
2012 value is $550 and rate is $150 increase
Answered by Anonymous
150t+250*** my answer
Answered by Steve
looks good

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