Asked by Anonymous
The tri county schools are participating in a renaissance faire. The team from Appleton High school has designed a pennant to fly over its team tent.The pennant is in the shape of a triangle. The longest side is 3 inches longer than half the middle length side. If the team captain bought 72 of satin edging for the banner , and there were 4 inches left over after the pennant was made , what are the dimensions of the pennant?
Answers
Answered by
Reiny
let the shortest side be a, let the middle side be b, then the longest side is
b/2 + 3.
so the perimeter is a + b + b/2 + 3
then a+b+b/2+3 + 4 = 72
a = 65 - 3b/2
but b/2+3 is said to be the longest side, so
b/2 + 3 > b
b + 6 > 2b
b < 6
let b = 2, then a = 62 , other side is 4 , no such triangle is possible
let b = 4, then a = 59, other side is 5, no such triangle
let b = 30, then a = 20, other side is 18
This does form a triangle, but 18 comes from the definition of the "longest" side. This is a contradiction. The same would be true for all b > 6
This question does not have a solution. Check your typing, or did you forget some other information?
b/2 + 3.
so the perimeter is a + b + b/2 + 3
then a+b+b/2+3 + 4 = 72
a = 65 - 3b/2
but b/2+3 is said to be the longest side, so
b/2 + 3 > b
b + 6 > 2b
b < 6
let b = 2, then a = 62 , other side is 4 , no such triangle is possible
let b = 4, then a = 59, other side is 5, no such triangle
let b = 30, then a = 20, other side is 18
This does form a triangle, but 18 comes from the definition of the "longest" side. This is a contradiction. The same would be true for all b > 6
This question does not have a solution. Check your typing, or did you forget some other information?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.