Question
If diameter of iron pipe is 2.8cm
and 1mm thickness is melted and cylindrical rod of same length is formed find diameter of rod
and 1mm thickness is melted and cylindrical rod of same length is formed find diameter of rod
Answers
This could be a really tough question (with some x values) if you don't know the length of the original iron pipe...
Do you?
If not you could work with the assumption of a 1 m pipe.
Do you?
If not you could work with the assumption of a 1 m pipe.
depending on whether the rod's inside or outside diameter is 28mm, the cross-section of iron area is either
π(28^2-27^2) = 55π cm^2
or
π(29^2-28^2) = 57π cm^2
So, the radius of the solid rod (πr^2) is either √55 or √57 cm
π(28^2-27^2) = 55π cm^2
or
π(29^2-28^2) = 57π cm^2
So, the radius of the solid rod (πr^2) is either √55 or √57 cm
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