Asked by Jack
Prove that tan4x=4tanx(1-tan²x)/1-6tan²x+tan⁴x.
Answers
Answered by
Steve
I think the best way to start would be
tan 4x = 2*tan 2x/(1-tan^2 2x)
= 2(2tanx/(1-tan^2x)) / (1-(2tanx/(1-tan^2x))^2)
Now place top and bottom over a common denominator of (1-tan^2x)^2
and you should see things going where you want them.
tan 4x = 2*tan 2x/(1-tan^2 2x)
= 2(2tanx/(1-tan^2x)) / (1-(2tanx/(1-tan^2x))^2)
Now place top and bottom over a common denominator of (1-tan^2x)^2
and you should see things going where you want them.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.