Asked by harley
A biologist grows a culture of bacteria as part of an experiment. At the start of the experiment, there are 75 bacteria in the culture. The biologist observes that the population of bacteria dobules evert 18 minutes. Which of the following equations best models the number, n, of bacteria t hours after the start of the experiment.
a. n=75(2)^t/18
b. n=75(1+t/18)
c. n=75(2)^10t/3
d. n=75(1+(10/3)t)
a. n=75(2)^t/18
b. n=75(1+t/18)
c. n=75(2)^10t/3
d. n=75(1+(10/3)t)
Answers
Answered by
bobpursley
a would be a perfect answer if t was in minutes. But it is in hours. There are 10/3 eighteen minutes in an hour, and the number of doubling periods is 10t/3
Answered by
Damon
when t = 0, n = 75 (note 2^0 = 1)
when t = 18, n = 75 * 2^1 (note 18/18 = 1)
when t = 36 , n = 75 * 2^2 (note 36/18 = 2 ) etc
when t = 18, n = 75 * 2^1 (note 18/18 = 1)
when t = 36 , n = 75 * 2^2 (note 36/18 = 2 ) etc
Answered by
Damon
whoops, sorry, did not notice the hours/minutes problem
Answered by
scott
the 10t/3 that bob talks about is in c
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