Question

4. A 1500 kg car starts from rest and drives around a flat 50 m diameter circular track. The
forward force provided by the car’s wheels is a constant 1000 N.
a. What are the magnitudes and direction of the car’s acceleration at t = 10 s?
b. If the car has rubber tires and the track is concrete (µs = 1.00), at what time does
the car begin to slide?

Answer 1

a. F=ma, a=Force/mass, and that acceleration is tangential to the circle at each instant.
b.
force friction=mu*mg
force cnetripetal= mv^2/r

at sliding time, they are equal, and v=a*time or
mu*g=a^2*time^2/r
solve for time

Answer 2

2850