Asked by Kleen
An ordinary die is thrown seven times.find the probability of obtaining exactly three sixes
Answers
Answered by
Reiny
prob(six) = 1/6
prob(not six) = 5/6
prob(as stated) = C(7,3) (1/6)^3 (5/6)^4
= 35(1/216)(625/1296) = ....
prob(not six) = 5/6
prob(as stated) = C(7,3) (1/6)^3 (5/6)^4
= 35(1/216)(625/1296) = ....
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