Question
An ordinary die is thrown seven times.find the probability of obtaining exactly three sixes
Answers
Reiny
prob(six) = 1/6
prob(not six) = 5/6
prob(as stated) = C(7,3) (1/6)^3 (5/6)^4
= 35(1/216)(625/1296) = ....
prob(not six) = 5/6
prob(as stated) = C(7,3) (1/6)^3 (5/6)^4
= 35(1/216)(625/1296) = ....