Asked by Zack
Width of a wall is 4 inches less then the length. The border that surrounds the wall is 2 inches wide and has an area of 240 square inches. What are dimensions
Answers
Answered by
Steve
the area of the border is the total area minus the area of the wall. So,
if the width of the wall is w, then since there is border on each side, we need
(w+4)(w+4+4)-w(w+4) = 240
8(w+4) = 240
w=26
The wall is 26x30
if the width of the wall is w, then since there is border on each side, we need
(w+4)(w+4+4)-w(w+4) = 240
8(w+4) = 240
w=26
The wall is 26x30
Answered by
scott
let w = width , length = w + 4 ... cross section area = w (w + 4)
width with border = w + (2 * 2) = w + 4
length with border = w + 4 + (2 * 2) = w + 8
area with border = (w + 4) (w + 8)
area of border = [(w + 4) (w + 8)] - [w (w + 4)] = 240
solve for w , then substitute back to find the length
width with border = w + (2 * 2) = w + 4
length with border = w + 4 + (2 * 2) = w + 8
area with border = (w + 4) (w + 8)
area of border = [(w + 4) (w + 8)] - [w (w + 4)] = 240
solve for w , then substitute back to find the length