Ask a New Question

Question

Using the binomial theorem, Find the first three terms in the expansion of (x^2+2y^3)^20
7 years ago

Answers

Steve - eh?
They are, of course,

20C0 (x^2)^20(2y^3)^0 + 20C1(x^2)^19(2y^3)^1 + 20C2 (x^2)^18(2y^3)^2
x^40 + 40x^38y^3 + 760x^36y^6
7 years ago

Related Questions

Use the Binomial Theorem to find the fifth term in the expansion (2x+3y)^5. 5!/(5-k)^x^5-kyk 5!/... use the binomial theorem to expand and simplify (y^2-2)^6 )(y^2+2)^6 use the binomial theorem to expand the binomial (x+5)^5 I have tried it like 4 times but i canno... use the binomial theorem to expand the binomial (x-5)^6 Use the binomial theorem to expand (2-1/4X)⁴ Use the Binomial Theorem or Pascal's Triangle to expand the binomial. (2x - 3y)^3 Use the Binomial Theorem to find the binomial expansion of the expression. (s-5v)5 s5 -5s4v +... Using the Binomial Theorem, what would be the coefficient of the sixth term in the binomial expansio...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use