Asked by Lisa
In a survey, 20 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $30 and standard deviation of $2. Find the margin of error for a 99% confidence level.
Answers
Answered by
PsyDAG
Z = (score-mean)/SEm
SEm = SD/√n
The error would be .005 at each end, which gives you a Z score of ±1.645.
I'll let you do the calculations.
SEm = SD/√n
The error would be .005 at each end, which gives you a Z score of ±1.645.
I'll let you do the calculations.
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