this question came up in my work, and i don't remember reading about it in my book. can you tell me what it is asking for, and how to do it..

if the change in position delta x is related to velocity v(with units of m/s) in the equation delta x=Av, the constant A has which dimensions?

i have no clue how to even start figuring this out

4 answers

position units = velocity * time units
meters = (meters/second) * seconds
im still kinda confused...would the answer be m/s^2...?
delta position=velocity*deltatime
Units: meters=m/s * sec
So would not A be seconds?
yes, thnks alot