Asked by iraiven

the outer rectangle is 32 cm by 20 cm.the inner rectangle is 26 cm by 14 cm .all measurement are given to the nearest centimetres.calculate the lower bound of the perimeter of the outer rectangle.

Answers

Answered by Steve
The outer rectangle could be as small as 31.5 by 19.5, so the lower bound on the perimeter would be

2(31.5+19.5) = 102 cm
Answered by chase
Hello steve , I believe you answered this before.
Insert <, >, or = to make the sentence true.
-1/3 -2/5

A.)=
B.)>
C.)<
Answered by Steve
-1/3 = -0.333
-2/5 = -0.400

so, what do you think? If you're not sure, plot them both on the number line, and see where they lie.
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