Asked by Anonymous
A car moving at 89 km per hour is subjected to a retardation to brought to rest in 70 second. Find retardation and distance
Answers
Answered by
bobpursley
change km/hr to m/s
vf=vi+at
vf=0 you can solve for a, the deacceleration. For distance,
avg velocity= vi/2 so distance= avgvelocity*time
vf=vi+at
vf=0 you can solve for a, the deacceleration. For distance,
avg velocity= vi/2 so distance= avgvelocity*time
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