Write the fraction you would use to change the base for log8 15 (base 6)
2 answers
i meant base 8
let x = log8 15
by definition: 8^x = 15
now take log of both sides, (base 10 is understood)
log (8^x) = log 15
x log 8 = log 15
x = log15/log8
in general: loga b = log b/log a , where a ≠ 1, a > 0
by definition: 8^x = 15
now take log of both sides, (base 10 is understood)
log (8^x) = log 15
x log 8 = log 15
x = log15/log8
in general: loga b = log b/log a , where a ≠ 1, a > 0