Asked by Anonymous
How does .08/(.08+.92(2/23)^t/4) become 2/(2+23(2/23)^t/4)? I don't understand how .08 becomes 2 and .92 becomes 23.
Answers
Answered by
Jerry
Divide numerator and denominator by .04
Answered by
Reiny
They multiplied top and bottom by 25
.08/(.08+.92(2/23)^t/4)
= .08<b>(25)</b> / [<b>(25)</b> ((.08+.92(2/23)^t/4) ]
= 2 / (2 + 23(2/23)^t/4 )
.08/(.08+.92(2/23)^t/4)
= .08<b>(25)</b> / [<b>(25)</b> ((.08+.92(2/23)^t/4) ]
= 2 / (2 + 23(2/23)^t/4 )
Answered by
Reiny
notice Jerry's answer and mine are the same thing, since
k รท .04
= k x 1/.04
= k x 25
k รท .04
= k x 1/.04
= k x 25
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