Asked by maath
The volume enclosed by a sphere of radius r is (4/3)πr^3. The surface area of the same sphere is 4πr^2. You may already have noticed that the volume is exactly (1/3)r times the surface area. Explain why this relationship should be expected. One way is to consider a billion-faceted polyhedron that is circumscribed about a sphere of radius r; how are its volume and surface area related?
Answers
Answered by
Steve
The volume of a pyramid is 1/3 Bh
Consider the many-faceted polyhedron as a collection of pyramids.
Each small patch -- of area, say, B, of the surface of the sphere is the base of a pyramid of height r, giving it a volume of 1/3 Br.
Adding up all the patches, you get the surface of the sphere, multiplied by 1/3 r, giving the volume of the sphere.
Consider the many-faceted polyhedron as a collection of pyramids.
Each small patch -- of area, say, B, of the surface of the sphere is the base of a pyramid of height r, giving it a volume of 1/3 Br.
Adding up all the patches, you get the surface of the sphere, multiplied by 1/3 r, giving the volume of the sphere.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.