Hi, I am trying to do homework for my math 012 class- solving linear equations- and I need help with 9 of the problems. I would really appreciate any help with this. I can do the problems and send them to you, or however you prefer.
Thanks!
6 answers
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ok thanks!
-6(1x-3)-26=-8
-6(1x-3)-26=-8
-6x+18-26=-8
-6x+44=-8
-44 -44
-6x=36
-6 =-6
x=6
-6(1x-3)-26=-8
-6(1x-3)-26=-8
-6x+18-26=-8
-6x+44=-8
-44 -44
-6x=36
-6 =-6
x=6
It is conventional to just write x, instead of 1x, wheneve the coefficient of an algebraic variable is 1.
There is a mistake in what you did.
Let's take a look.
-6(x-3)-26 = -8
-6x +18 -26 = -8
(You got that far OK)
-6x - 8 = -8
-6x = 0
x = 0
There is a mistake in what you did.
Let's take a look.
-6(x-3)-26 = -8
-6x +18 -26 = -8
(You got that far OK)
-6x - 8 = -8
-6x = 0
x = 0
One more thing with this problem if you can explain for me. how come in the forth step, it is -6x=0?
I added 8 to both sides of the equation, thus eliminating it.
how to solve this math problem x/3 - 8 = -2
3 answers