Asked by DIMKA SULEIMAN
A Boy Stand At A Certain Distance From A Large Building And Blow A Whitle After 2.3s He Hear It Echo.He Move 50m Toward The Building And Blow He Whitle Again, This Time It Echo Reach Him After 2.0s.Calculate The(1)boy Original Distance From The Building (2)the Speed Of Sound In Air?
Answers
Answered by
bobpursley
distanceofecho=2*distancefrombuilding
distanceofecho=vsound*time
so between the two echos...
50*2=vsound(2.3-2.0)
vsound=100m/.3sec=333 m/s
distanceofecho=vsound*time
so between the two echos...
50*2=vsound(2.3-2.0)
vsound=100m/.3sec=333 m/s
Answered by
Henry
1. r *( 2.3/2) = d,
r = 0.87d.
r *( 2/2) = d-50,
Replace r with 0.87d:
0.87d * 1 = d-50,
d = 384.6 m.
2. r = 0.87d = 0.87 * 384.6 = 335 m/s.= Speed of sound.
r = 0.87d.
r *( 2/2) = d-50,
Replace r with 0.87d:
0.87d * 1 = d-50,
d = 384.6 m.
2. r = 0.87d = 0.87 * 384.6 = 335 m/s.= Speed of sound.
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