Asked by George
What is the complete redox reaction of KMnO4 against (NH4)2Fe(SO4)2
Answers
Answered by
bobpursley
Fe(NH4)2(SO4) is a 1:1 (molar) mixture of FeSO4 and (NH4)2SO4.
Fe(NH4)2(SO4)2·6H2O + KMnO4 --> ??
From a lab session I've found that oxygen gas is one of the products and that Fe(NH4)2(SO4)2·6H2O gets oxidised, but I'm not very sure about what other products are formed. I've tried looking for the answers on google but all I've found are the redox equations. I've included them in case they're helpful:
MnO4- + 8 H+ + 5e- --> Mn+2 + 4 H2O reduction of Mn+7
Fe +2 --> Fe +3 + e- oxidation of Fe+2
MnO4-+ 5 Fe+2 + 8 H+ --> Mn+2 + 5 Fe+3 + 4 H2O REDOX EQN
There are no products except H2O, In general there is no such thing as a 'full equation'. You end up with solution containing mixture of ions, not well defined salts. In this particular case you may list all possible (and necessary) sulfates as products, but when there are several anions things get messy.
Fe(NH4)2(SO4)2·6H2O + KMnO4 --> ??
From a lab session I've found that oxygen gas is one of the products and that Fe(NH4)2(SO4)2·6H2O gets oxidised, but I'm not very sure about what other products are formed. I've tried looking for the answers on google but all I've found are the redox equations. I've included them in case they're helpful:
MnO4- + 8 H+ + 5e- --> Mn+2 + 4 H2O reduction of Mn+7
Fe +2 --> Fe +3 + e- oxidation of Fe+2
MnO4-+ 5 Fe+2 + 8 H+ --> Mn+2 + 5 Fe+3 + 4 H2O REDOX EQN
There are no products except H2O, In general there is no such thing as a 'full equation'. You end up with solution containing mixture of ions, not well defined salts. In this particular case you may list all possible (and necessary) sulfates as products, but when there are several anions things get messy.
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