The region under the following curve is rotated about the x-axis. Find the volume of the resulting solid.

y=13tan(x)^2, 0<x<pi/4

1 answer

Volume =
Integral pi [y(x)]^2 dx
x = 0 to pi/4

The integral of tan^4(x), which you will need, can be found in a table of integrals. It uses a recursion formula.

INT tan^4(x) = (1/3)tan^3x - (1/2)tan^2x + tan x - x
Similar Questions
  1. Let S be a region bounded by the curve y=x+cosxand the line y=x as shown in the given figure. Find the volume of the solid
    1. answers icon 1 answer
  2. The region A is bounded by the curve y=x^2-5x+6 and the line y = -x + 3.(a) Sketch the line and the curve on the same set of
    1. answers icon 1 answer
    1. answers icon 1 answer
  3. Let R be the region bounded by the x-axis, x = 5 and the curvey = x. This region is rotated around the x-axis. Find the volume
    1. answers icon 1 answer
more similar questions