Asked by jach
The region under the following curve is rotated about the x-axis. Find the volume of the resulting solid.
y=13tan(x)^2, 0<x<pi/4
y=13tan(x)^2, 0<x<pi/4
Answers
Answered by
drwls
Volume =
Integral pi [y(x)]^2 dx
x = 0 to pi/4
The integral of tan^4(x), which you will need, can be found in a table of integrals. It uses a recursion formula.
INT tan^4(x) = (1/3)tan^3x - (1/2)tan^2x + tan x - x
Integral pi [y(x)]^2 dx
x = 0 to pi/4
The integral of tan^4(x), which you will need, can be found in a table of integrals. It uses a recursion formula.
INT tan^4(x) = (1/3)tan^3x - (1/2)tan^2x + tan x - x
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