Question
A rectangular field is four times as long as it is wide. If the perimeter of the field is 750 feet, what are the dimensions of the field?
Answers
Ms. Sue
Let w represent the width.
2 (4w) + 2w = 750
8w + 2w = 750
10w = 750
w = 75
2 (4w) + 2w = 750
8w + 2w = 750
10w = 750
w = 75
width 50 and length 200
Let's L=4w
2(L+w)=P
2(4w+w)=750
8w+2w=750
10w=750
W=75
2(L+w)=P
2(4w+w)=750
8w+2w=750
10w=750
W=75
So the width of the field is 75 feet.
To find the length, we can use L=4w.
L=4(75)
L=300
So the dimensions of the field are 75 feet by 300 feet.
To find the length, we can use L=4w.
L=4(75)
L=300
So the dimensions of the field are 75 feet by 300 feet.
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