Asked by jasort120
i need help solving the system by addition.
5x-7y=5
x+3y=1
this is what i think but i am not sure
3y=-x+1
y= -(1/3)x+(1/3)
5x - 7 (-1/3x + 1/3) = 5
5x+2.3333331x-2.3333331=5
7.3333331x-2.3333331=5
7.3333331x=7.3333331
x=1
x+3y=1
1+3y=1
3y=1-1
3y=0
y=0
so my solutions i get is
x = 1 and y = 0
You have the solution ,but you did not get it by addition.
5x-7y=5
x+3y=1
Multiply the second equation by -5
5x-7y=5
-5x-15y=-5
Now add the equations.
0x - 22y= 0
solve, y=0
5x-7y=5
x+3y=1
Put y=0 into either equation, and solve for x.
5x-7y=5
x+3y=1
this is what i think but i am not sure
3y=-x+1
y= -(1/3)x+(1/3)
5x - 7 (-1/3x + 1/3) = 5
5x+2.3333331x-2.3333331=5
7.3333331x-2.3333331=5
7.3333331x=7.3333331
x=1
x+3y=1
1+3y=1
3y=1-1
3y=0
y=0
so my solutions i get is
x = 1 and y = 0
You have the solution ,but you did not get it by addition.
5x-7y=5
x+3y=1
Multiply the second equation by -5
5x-7y=5
-5x-15y=-5
Now add the equations.
0x - 22y= 0
solve, y=0
5x-7y=5
x+3y=1
Put y=0 into either equation, and solve for x.
Answers
Answered by
Anonymous
{5x-3y=11
{3x+y=1
{3x+y=1
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