Asked by Austin
Write the equation in slope-intercept form of the line that is parallel to the given line and passes through the given point.
Y=2x+1; (5,-1)
Y=2x+1; (5,-1)
Answers
Answered by
MsPi_3.14159265
Well... you know the form is y=mx +b where m is the slope.
So take the slope from Y=2x+1...which is the 2 so
You obtain Y=2x +b
now sub in (5, -1) which go in for the (x,y) the x and y in the equation y=2x+b, and solve for b :)
We would be happy to check your final answer :)
So take the slope from Y=2x+1...which is the 2 so
You obtain Y=2x +b
now sub in (5, -1) which go in for the (x,y) the x and y in the equation y=2x+b, and solve for b :)
We would be happy to check your final answer :)
Answered by
Austin
y=2x+b
-1=2(5)+b
I always get stuck around this part, have I been doing everything alright up to this point, and what steps do I need in order to solve it
-1=2(5)+b
I always get stuck around this part, have I been doing everything alright up to this point, and what steps do I need in order to solve it
Answered by
Damon
-1=2(5)+b yes, correect
now
-1 = 10 + b
b = -11
so
y = 2 x - 11
now
-1 = 10 + b
b = -11
so
y = 2 x - 11
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