A slice of pizza has 500 kcal. If we could burn the pizza and use all the heat to warm a 50–L container of cold water, what would be the approximate increase in the temperature of the water?

Question

bobpursley · Answer

5E5cal=50kg*80cal/g*deltaT deltaTemp=5E4/(5E4*80) deg C check those numbers. 50 liters is a lot of water.

ash · Answer

A slice of pizza has 500 kcal. If we could burn the pizza and use all the heat to warm a 50-L container of cold water, what would be the approximate increase in the temperature of the water?