Asked by Jack

A slice of pizza has 500 kcal. If we could burn the pizza and use all the heat to warm a 50–L container of cold water, what would be the approximate increase in the temperature of the water?
Answered by bobpursley
5E5cal=50kg*80cal/g*deltaT

deltaTemp=5E4/(5E4*80) deg C
check those numbers. 50 liters is a lot of water.
Answered by ash
A slice of pizza has 500 kcal. If we could burn the pizza and use all the heat to warm a 50-L container of cold water, what would be the approximate increase in the temperature of the water?
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