Simple reactions occur for one of three reasons.
a. a ppt is formed
b. a gas is formed
c. a non-electrolyte is formed.
hint: in 1, Al(OH)3 is a ppt
in 3 H2O is a non-electrolyte.
1.) Ca(OH)2 (aq) + Al(NO3)3 (aq) →
2.) Cu(C2H3O2)2 (aq) + Na2SO4 (aq) →
3.) H2SO4 (aq) + KOH (aq) →
a. a ppt is formed
b. a gas is formed
c. a non-electrolyte is formed.
hint: in 1, Al(OH)3 is a ppt
in 3 H2O is a non-electrolyte.
1. Ca(OH)2 (aq) + Al(NO3)3 (aq):
To determine if a reaction will occur, we need to check if there is a possibility of a double displacement reaction, where the cations and anions from each compound switch places. In this case, we have Calcium hydroxide (Ca(OH)2) and Aluminum nitrate (Al(NO3)3).
The cations present are Ca²⁺ and Al³⁺, and the anions are OH⁻ and NO₃⁻. By examining the charges, we can see that Ca²⁺ can react with NO₃⁻, and Al³⁺ can react with OH⁻.
The balanced equation for this reaction is:
Ca(OH)2 (aq) + Al(NO3)3 (aq) -> Ca(NO3)2 (aq) + Al(OH)3 (s)
2. Cu(C2H3O2)2 (aq) + Na2SO4 (aq):
Similar to the previous example, we'll look for a double displacement reaction. Here, we have Copper acetate (Cu(C2H3O2)2) and Sodium sulfate (Na2SO4).
The cations present are Cu²⁺ and Na⁺, and the anions are C2H3O2⁻ and SO₄²⁻. By examining the charges, we can see that Cu²⁺ can react with SO₄²⁻, and Na⁺ can react with C2H3O2⁻.
The balanced equation for this reaction is:
Cu(C2H3O2)2 (aq) + Na2SO4 (aq) -> CuSO4 (aq) + 2NaC2H3O2 (aq)
3. H2SO4 (aq) + KOH (aq):
In this case, we have Sulfuric acid (H2SO4) and Potassium hydroxide (KOH).
From the reactants, we can see that H⁺ from H2SO4 reacts with OH⁻ from KOH to form water (H2O). Potassium (K⁺) and sulfate (SO₄²⁻) ions do not participate in the reaction.
The balanced equation for this reaction is:
H2SO4 (aq) + 2KOH (aq) -> 2H2O (l) + K2SO4 (aq)
Remember to always balance the equation to ensure conservation of mass and charge.