Just before a bouncy ball hits a wall, it is traveling parallel to the ground at 18 m/s, and it then bounces directly backwards at 17 m/s. The interaction time with the wall was 0.40 ms (4.0 x 10-4 s). If the ball's mass is 0.17 kg, what is the average magnitude of the force of the wall on the ball during their interaction?

asked by Sam

6 years ago

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1 answer

V = Vo + a*t = 17 m/s,
18 + a*4*10^-4 = 17,
a = ?. (It will be negative.)
F = M*a.

answered by Henry

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Question

Just before a bouncy ball hits a wall, it is traveling parallel to the ground at 18 m/s, and it then bounces directly backwards at 17 m/s. The interaction time with the wall was 0.40 ms (4.0 x 10-4 s). If the ball's mass is 0.17 kg, what is the average magnitude of the force of the wall on the ball during their interaction?

1 answer

V = Vo + a*t = 17 m/s,
18 + a*4*10^-4 = 17,
a = ?. (It will be negative.)
F = M*a.

Henry · Answer

V = Vo + a*t = 17 m/s, 18 + a*4*10^-4 = 17, a = ?. (It will be negative.) F = M*a.