Question
Just before a bouncy ball hits a wall, it is traveling parallel to the ground at 18 m/s, and it then bounces directly backwards at 17 m/s. The interaction time with the wall was 0.40 ms (4.0 x 10-4 s). If the ball's mass is 0.17 kg, what is the average magnitude of the force of the wall on the ball during their interaction?
Answers
Henry
V = Vo + a*t = 17 m/s,
18 + a*4*10^-4 = 17,
a = ?. (It will be negative.)
F = M*a.
18 + a*4*10^-4 = 17,
a = ?. (It will be negative.)
F = M*a.