Asked by Mimi
a wave function expressing displacement (y) as a function of its (x) and time (t) is given as y = P log (Qx + Rt)
Which of the following expressions has dimensions different from one another?
(1) yR
(2) PR
(3) R/Q
(4) QR
Which of the following expressions has dimensions different from one another?
(1) yR
(2) PR
(3) R/Q
(4) QR
Answers
Answered by
bobpursley
and your thinking is?
Answered by
Arnab
4.QR
Because log(x) is dimensionless. Here (x)=(Qx+Rt) So [Q][x]=[M^0][L^0][T^0] So [Q]=[L^-1]
Then [R]=[T^-1] & [P]=[L] ( Same as dimension of y= displacement)
Then the only answer is QR which have different dimension from the other three options.
Because log(x) is dimensionless. Here (x)=(Qx+Rt) So [Q][x]=[M^0][L^0][T^0] So [Q]=[L^-1]
Then [R]=[T^-1] & [P]=[L] ( Same as dimension of y= displacement)
Then the only answer is QR which have different dimension from the other three options.
Answered by
Anonymous
Very bad
Answered by
Anonymous
I didn't understand
Answered by
shruti
Not understandable
Answered by
AY
Y=Plog(Qx+e^-Rt)
In log(x) x is dimensionless being a constant
So (Qx+e^-Rt) = 1
Also dimensions of Qx= dimensions of e^-Rt as only similar quantities can be added or subtracted
Hence Qx=1
Q= x^-1=[L^-1]
Similarly, -Rt = 1
R= [T^-1]
Y=p=[L]
Put these values in the options and find the odd one out i.e. QR
In log(x) x is dimensionless being a constant
So (Qx+e^-Rt) = 1
Also dimensions of Qx= dimensions of e^-Rt as only similar quantities can be added or subtracted
Hence Qx=1
Q= x^-1=[L^-1]
Similarly, -Rt = 1
R= [T^-1]
Y=p=[L]
Put these values in the options and find the odd one out i.e. QR
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