Asked by alice
how do you find the solution to
(dy/dx)+ycos(x)=6cos(x)
when the initial conditions y(0)=8?
all i can get is y(x)=e^sin(x) + 7
(dy/dx)+ycos(x)=6cos(x)
when the initial conditions y(0)=8?
all i can get is y(x)=e^sin(x) + 7
Answers
Answered by
bobpursley
again, this is a first order linear diff equation, see the practical steps in the link below (get the form, then the integrating factor, and evaluate.
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