Question

the diameter of a copper atom is roughly 1.3×10^-10 m. how many times can you divide evenly a piece of 10cm copper wire until it is reduce to two seperate copper atoms? (assume there are appropriate tools for the procedure and that copper atoms are lined up in a straight line in contact with each other)

Answer 1

2 * 1.3E-8 = 10 / 2^n

2^(n + 1) = 10 / 1.3E-8

(n + 1) log(2) = log(10 / 1.3E-8)