Question

#2) Consider the preciditation reaction of a solution containing 3.50 grams of sodium phosphate mixed with a solution containing 6.40 grams of barium nitrate. How many grams of Barium phosphate can form?
Ba(NO3 )2 + Na3 PO4 yields Ba3 (PO 4 )2 + NaNO3



#2b) If the actural yield of the previous problem was 4.70 grams of barium phosphate. What is the % yield?



i got 4.91g Ba3(PO4)2 as the limiting reagent for number 2. so how do i do 2b??

Answer 1

I checked it, too, and 4.01 Ba3(PO4)2 is correct BUT Ba3(PO4)2 is not the limiting reagent. The limiting reagent is the Ba(NO3)2. Ba3(PO4)2 is the product.
How to do the percent?
The 4.91 g Ba3PO4)2 is the theoretical yield. The actual yield is 4.70 g.
%yield = (actual yield)/(theoretical yield)*100.