Asked by Gagan
                sinØ (1+ tanØ) + cosØ(1+ cotØ) = (secØ + cosecØ)
            
            
        Answers
                    Answered by
            Steve
            
    sinØ (1+ tanØ) + cosØ(1+ cotØ)
sinØ(sinØ+cosØ)/cosØ + cosØ(sinØ+cosØ)/sinØ
tanØ(sinØ+cosØ) + cotØ(sinØ+cosØ)
(tanØ+cotØ)(sinØ+cosØ)
(sin^2Ø+cos^2Ø)/(sinØcosØ) (sinØ+cosØ)
(sinØ+cosØ)/(sinØcosØ)
1/cosØ + 1/sinØ
secØ+cscØ
    
sinØ(sinØ+cosØ)/cosØ + cosØ(sinØ+cosØ)/sinØ
tanØ(sinØ+cosØ) + cotØ(sinØ+cosØ)
(tanØ+cotØ)(sinØ+cosØ)
(sin^2Ø+cos^2Ø)/(sinØcosØ) (sinØ+cosØ)
(sinØ+cosØ)/(sinØcosØ)
1/cosØ + 1/sinØ
secØ+cscØ
                    Answered by
            Reiny
            
    I assume you are proving this identity to be true.
What have you done so far?
    
What have you done so far?
                    Answered by
            Boss
            
    Nice Question 
Answer is very easy
some one has already solved...........
    
Answer is very easy
some one has already solved...........
                    Answered by
            A. 
            
    Good
    
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