Asked by Robert
A cube made ouk and side 15cm floats in water with 10.5cm of it's depth below the surfaces and with it's side's vertical what is density of oak
Answers
Answered by
Damon
volume of oak under water = 15*15 * 10.5
so Archimedes says
mass of oak = density of water * volume under water = 1 g/cm^3 * 15*15 * 10.5
total volume of oak = 15*15*15
density = mass/volume = 1 g/cm^3 * 10.5/15
so Archimedes says
mass of oak = density of water * volume under water = 1 g/cm^3 * 15*15 * 10.5
total volume of oak = 15*15*15
density = mass/volume = 1 g/cm^3 * 10.5/15
Answered by
Anonymous
That's actually wrongðŸ˜
Answered by
It is wrong
It is really tough and wrong
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