Asked by gared
Question 11 Unsaved
A car of mass 1200 kg travels along a horizontal road at a speed of 10 m s-1. At the time
it begins to accelerate at 0.2 m s-2, the total resistive force acting on the car is 160 N. What is
the total output power developed by the car as it begins the acceleration?
A car of mass 1200 kg travels along a horizontal road at a speed of 10 m s-1. At the time
it begins to accelerate at 0.2 m s-2, the total resistive force acting on the car is 160 N. What is
the total output power developed by the car as it begins the acceleration?
Answers
Answered by
Anonymous
call F = force exerted on car by tires through engine power
total horizontal force on car = force exerted by tires - resistive force
= F - 160
so
F - 160 = m a
F = 160 + 1200*0.2 = 160 +240 = 400 N
power = 400 * speed = 400 * 10 = 4000 Joules/second or Watts
total horizontal force on car = force exerted by tires - resistive force
= F - 160
so
F - 160 = m a
F = 160 + 1200*0.2 = 160 +240 = 400 N
power = 400 * speed = 400 * 10 = 4000 Joules/second or Watts
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