Asked by hewhomustbenamed82
A bullet of mass 8 gram is fired into a block of mass 2,5 kg initially at rest at the edge of a frictionless table of height 1 m. The bullet remains in the block, and after impact the block lands a distance 2 m from the bottom of the table. Determine the initial speed of the bullet.
Answers
Answered by
Damon
first figure out how long it took the block to fall to the floor:
h = (1/2) g t^2
t = sqrt (2 h/g)
so it went 2 meters in t seconds
so the horizontal speed was
u = 2/t
NOW you have a conservation of momentum problem
u(2.5 + .008) = .008 v
solve for v
h = (1/2) g t^2
t = sqrt (2 h/g)
so it went 2 meters in t seconds
so the horizontal speed was
u = 2/t
NOW you have a conservation of momentum problem
u(2.5 + .008) = .008 v
solve for v