Asked by kumal

if x=1/7+4 root 3 and y=1/7-4 root 3, then find the value of x2+ y2


Answered by Reiny
sum of roots = x+y = 1/7 + 4 + 1/7 - 4 = 2/7
product of roots = xy = (1/7 + 4)(1/7 - 4) = 1/49 - 16 = -783/49

(x+y)^2 = x^2 + y^2 + 2xy
x^2 + y^2 = (x+y)^2 - 2xy
= (2/7)^2 - (-783/49)
= ...
continue
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