Question

174520 = (massboiled) (2260)

.1716 = massboiled

so .1716?



Suppose a burner transfers 325 kJ of energy to 450 kg of liquid water at 20 C degrees. What mass of the water would be boiled away?

The first energy going in heats the water:

energy=mass*c*(100-20) Then subtract that from the intial 325kJ.

Then, you can figure the mass of water boiled away:

heatleft=massboiled*Lv Where Lv is the heat of vaporization.