Asked by physics

A 5.0 kg bucket of water is raised form a well by a rope. If the upward acceleratiopn of the bucket is 3.0 m/s^2 find the force exerted by the rope on the bucket of water

what exactly do i do here?
3.0 m/s^2 upward? is this the Fn? I have no idea how to do this problem...
Answered by drwls
The net force acting on the bucket is

Fn = T - Mg = M a

T is the tension in the rope.

T = M (g + a) = 12.8 m/s^2 * 5.0 kg = ?
Answered by physics
odd i never seen this formula before and we haven't goten to tension yet thank you
Answered by drwls
The formula I used is Newton's second law. You probably have heard about that. Tension is one of the two forces acting on the bucket. The other is the weight force, W = M a
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