Asked by Kiff
Points L and M are equidistant from another K. The bearing of L from K is 330 degree. The bearing of M from K is 220 degree. Calculate the bearing of M from L.
Answers
Answered by
Steve
since KL and KM are the same distance, triangle KLM is isosceles.
Angle K is 110°
Thus angles L and M are each 35°
The bearing of K from L is 330-180=150°
Add to that the 35° at angle L and M's bearing from L is 185°
Angle K is 110°
Thus angles L and M are each 35°
The bearing of K from L is 330-180=150°
Add to that the 35° at angle L and M's bearing from L is 185°
Answered by
henry2,
All angles are measured CW from +y-axis
Use unit vectors:
KL = 1[330o]
LK = 1[330-180] = 1[150o]
KM = 1[220o].
LM = ?
LM = LK + KM = 1[150] + 1[220].
LM = (1*sin150+1*sin220) + (1*cos150+1*cos220)I,
LM = -0.1428 - 1.632i,
TanA = X/Y.
A = 5 Degrees CW. = 85o CCW.
Use unit vectors:
KL = 1[330o]
LK = 1[330-180] = 1[150o]
KM = 1[220o].
LM = ?
LM = LK + KM = 1[150] + 1[220].
LM = (1*sin150+1*sin220) + (1*cos150+1*cos220)I,
LM = -0.1428 - 1.632i,
TanA = X/Y.
A = 5 Degrees CW. = 85o CCW.
Answered by
Tressy
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