Asked by madison

Complete the table for a savings account in which interest is compounded continuously. (Round your answers to four decimal places.)

Initial Investment: $350
Annual % Rate: %
Time to Double: yr
Amount After 10 Years: $435.21
Answered by Reiny
350 e^(10r) = 435.21
e^(10r) = 1.243457...
take ln of both sides:
10r = ln(1.243457..) = .2178955..
r = .02178955... or appr 2.1790%

now that you know the rate, for the doubling time ....
350e^(.02178955..t) = 700

I will let you solve for t
Answered by Emma
girl i don’t get this
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