Asked by Cali

Wile E Coyote, having missed the Road Runner, leaves the edge of the cliff at 29 m/s horizontal velocity. If the canyon is 104 m deep, how far from the base of the cliff does the coyote land?

Answers

Answered by bobpursley
time to fall: h=1/2 g t^2 solve for time t.
how for horizontal? d=vi*time
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