Asked by Anonymous
A 90kg halfback moving at 4.0m/s on an apparent breakaway for a touchdown is tackled from behind. When he was tackled by a cornerback of mass 78.3kg running at 7.48m/s in the same direction, what was their mutual speed immediately after the tackle?
how in the world do i solve this and wht is the proof for it?
how in the world do i solve this and wht is the proof for it?
Answers
Answered by
bobpursley
conservation of mometum applies:
90*4+78.3*7.48=(90+78.3)V solve for V
90*4+78.3*7.48=(90+78.3)V solve for V
Answered by
Anonymous
(original questioner)
ok so i got
360+584.684= 90v+78.3v
945.684=168.3v
945.684/168.3=168.3v/168.3
v=5.619037... and so on.
v= 5.62 m/s?
ok so i got
360+584.684= 90v+78.3v
945.684=168.3v
945.684/168.3=168.3v/168.3
v=5.619037... and so on.
v= 5.62 m/s?
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