Asked by Craig
1) show that: 1-cos2t divided by sin2t= TANt
2) show that: 1-(cos2t divided by (cos x cos)t)= (TAN x TAN)t
2) show that: 1-(cos2t divided by (cos x cos)t)= (TAN x TAN)t
Answers
Answered by
drwls
Is cos2t supposed to represent cos^2 t or cos (2t)?
In either case, the expression is not a correct identity. I believe you copied the problem incorrectly. It should be
1-cos^2t divided by sin^2t = 1
In your second question, (tan x tan) t is not an accepted notation. Do you mean tan^2 t?
[1 - cos^2 t]/cos^2 t = sin^2 t/ cos^2 t
= tan^2 t
In either case, the expression is not a correct identity. I believe you copied the problem incorrectly. It should be
1-cos^2t divided by sin^2t = 1
In your second question, (tan x tan) t is not an accepted notation. Do you mean tan^2 t?
[1 - cos^2 t]/cos^2 t = sin^2 t/ cos^2 t
= tan^2 t
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