Asked by Don'tknowtrig
Thank you Reiny for the last question! :)
If you or anyone else could help me with this other question, I'd really appreciate it!
Use the trigonometric subtraction formula for sine to verify the identity:
sin(pi/2-x)=cosx
Caluculation:
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Reason:
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prnt.sc/jns55q <--- copy and paste link
If you or anyone else could help me with this other question, I'd really appreciate it!
Use the trigonometric subtraction formula for sine to verify the identity:
sin(pi/2-x)=cosx
Caluculation:
-----
-----
-----
Reason:
-----
-----
-----
prnt.sc/jns55q <--- copy and paste link
Answers
Answered by
Reiny
prove sin(pi/2-x)=cosx , use the sin(A-B) = sinAcosB - cosAsinB expansion
LS = sin(π/2 - x)
= sinπ/2cos(x) - cosπ/2sinx , now recall sinπ/2 = 1, cosπ/2 = 0
= cosx - 0(sinx)
= cosx
= RS , all done
LS = sin(π/2 - x)
= sinπ/2cos(x) - cosπ/2sinx , now recall sinπ/2 = 1, cosπ/2 = 0
= cosx - 0(sinx)
= cosx
= RS , all done
Answered by
Don'tknowtrig
OMLLL! Thank you! Ily. :*