Asked by Oakly
Alice has $15 more than Barry. Charlene has 5/9 of the amount of Barrys money. If Alice has x dollars, how much money do they have altogether.
Answers
Answered by
Reiny
Alice ---- x
Barry ---- x-15
Charlene ---- (5/9)(x-15)
total = x + x-15 + 5x/9 - 25/3
= 2x + 5x/9 - 70/3
= 23x/9 - 70/3
or
= (23x - 210)/9
check:
suppose Alice has $45
then Barry has $30
Charlene has (5/9)(30) = 50/3
total = 45+30+50/3 = 275/3
according to my answer:
(23*45-210)/9 = 275/3 , I think I am right.
Barry ---- x-15
Charlene ---- (5/9)(x-15)
total = x + x-15 + 5x/9 - 25/3
= 2x + 5x/9 - 70/3
= 23x/9 - 70/3
or
= (23x - 210)/9
check:
suppose Alice has $45
then Barry has $30
Charlene has (5/9)(30) = 50/3
total = 45+30+50/3 = 275/3
according to my answer:
(23*45-210)/9 = 275/3 , I think I am right.
Answered by
Reese
so is the equation the final answer or is there an answer to that equation.
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